Saurabh Sinha <PICLIST@mitvma.mit.edu> wrote:

> I know this must be simple, but I cant remeber how this is done! [I am
> thinking along the way of an averaging integrator, but I am sure
> there's an easier way :-)] Please let me know or give me a hint!

Saurabh:

If you're feeding the averaged signal into a high-impedance input,
can't you simply find that average with a voltage divider formed from
two equal-valued resistors?  That should give you Vout = (Vin1 +
Vin2) / 2, right?

-Andy


=== Andrew Warren -- aiw@cypress.com
=== Principal Design Engineer
=== Cypress Semiconductor Corporation
===
=== Opinions expressed above do not
=== necessarily represent those of
=== Cypress Semiconductor Corporation

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