> leakage

0.5mW ERP isotropic point radiator? 0.5 mW/cm^2 at 5cm? 0.5mW/cm^2 at 5 cm
with a good 1 meter total seam length around the door, taken as a swath
only 1 cm wide totals 100cm x 0.5mW ~= 50mW total radiated (I am making
some assumptions about the radiation starting as a line and spreading to a
swath 1 cm wide exactly where the detector is).

0.5mW isotropic point radiator for an oven rated 700W that costs $150 is
something I really want to see ;-). It means an attenuation of 7x10^2 /
5x10^-4 ~= 1.4x10^6 = 1,400,000 times. That would be just too neat to be
achievable with a simple hinged door and some stamped steel and colored
glass.

Peter

PS: If you set up 2.4GHz video links and have the equipment you will 'see'
and cuss each and every MW in the neighbourhood (appear as mains noise
bars on AM links).

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