>         movlw   clock_bit
>         bsf   portb, clock_bit
>         xorwf protb
>
> The xorwf would invert whatever it read as the result of the bsf and
> there would be virtually no time for settling.

There would be no time at all for settling because the BSF write would occur
on the same clock edge as the XORWF read.


********************************************************************
Olin Lathrop, embedded systems consultant in Littleton Massachusetts
(978) 742-9014, olin@embedinc.com, http://www.embedinc.com

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