Ned, we are on the same wavelenght ! Cheers, Vasile On Fri, 27 Jul 2001, Ned Seith wrote: > Vasile, > > Your series capacitance voltage divider circuit has certainly received > criticism. > So I hope that I'm not kicking a dead horse. > While a transformer would definitely be the safest approach for the typical > hobbyist, I'm glad to see that there is someone who is willing to be more > intimate with the electrons. > The concept and configuration of your series capacitance voltage divider > circuit is fine. > I have designed industrial applications which have provided several amps of > current at low voltages from 220 Vac and 277 Vac mains using a series > capacitor. Industrial equipment and machines frequently use a series > capacitor instead of a transformer for providing lower voltages. > A few points: > I would not add a resistor in series with the capacitor (C9) as this will > vary the effective capacitance reactance which is providing the desirable > voltage drop and will also dissipate heat. > I would not add a resistor in parallel to the capacitor (C9) as this will > vary the effective capacitance reactance which is providing the desirable > voltage drop. This resistor would also dissipate heat. > I would not be too concerned with the capacitor (C9) remaining charged as > the approximate 6 mA current consumption from the voltage regulator will > quickly discharge the capacitor. UL and TUV stipulate that the voltage > potential on an unplugged power cord must diminish to 1/3 of the mains > voltage within 10 seconds. So, If I wanted to increase the rate at which > the capacitor discharges, I would place a resistor in parallel to (C5) on > the low voltage side of the circuit. > I would want a 1/4 amp fuse between the 220 Vac main and the series > capacitor (C9). > I would also want the series capacitor (C9) rated for 800 V to 1000 V. > If the series capacitor (C9) is getting warm at all, then the voltage > rating should be increased. > I would want the diode rectifiers voltage rating increased to 800 V to 1000 > V (1N4006, 1N4007) to assure that there is not any brief reverse conduction > during the delay of the capacitors charge cycle. > Otherwise, looks good to me. > Just a few comments from an old engineer. > > Sincerely, > Ned Seith > Nedtronics > 59 3rd Street > Gilroy, CA 95020 > (408) 842-0858 > G O T G A R L I C ? > GILROY GARLIC FESTIVAL 2001 ! > >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> > > At 12:10 PM 7/26/01 +0300, you wrote: > >I've done one, some time ago, see > >http://www.geocities.com/vsurducan/c520.htm > >at the bottom of the page, up to 150mA, but I don't recommend such power > >supplies for production devices ( maybe on 120V mains, only ) > >Note that in my design, the supply don't like to remain without load... > >Vasile > > > >On Thu, 26 Jul 2001, Roman Black wrote: > > > > > Alexandre Domingos F. Souza wrote: > > > > > > > > I designed a circuit with a PIC (12C508) that turns on and off a > > > >relay, controlled by an external source. The power to this circuit (around > > > >120mA) is a small transformer. I'd like to build a transformerless PSU > > into > > > >this circuit. But EVERY scheme I found on the internet was unusable. I saw > > > >something on the Embeeded Control Handbook from Microchip, but it only > > goes > > > >to (if I'm not mistaken) 45 mA. Maybe someone can help me to develop > > (or at > > > >least learn to) a simple transformerless PSU that 120mA. > > > > > > > > > Hi Alexandre! This can be done if you REALLY want > > > to do it. The Mchip app note shows 45mA, and that > > > is with a half-wave rectifier (two diodes). > > > > > > Just change to a proper rectifier bridge, this will > > > double the current to 90mA. Then using a 30% larger > > > value of the main Xc cap will give you 120mA. > > > This web page has Traffic.PDF sent by Richard Ottosen > > > which shows a larger current Xc supply with a > > > full-wave bridge: > > > http://centauri.ezy.net.au/~fastvid/tube4w.htm > > > > > > IMPORTANT! using a full wave rectifier will give > > > lethal voltages at ALL points of your 24v circuit. > > > You no longer have a reference ground! I know you > > > said you were using an optocoupler but remember at > > > all times this circuit is dangerous... > > > > > > Some handy points, you can get reliable relay > > > operation at half the hold current usng the old RC > > > trick, which gives it full current for pull-in > > > but only half current under hold. Costs one resistor > > > and one 470uF electro. Maybe this would get you > > > down to 60mA circuit current. I have used this trick > > > down to about 25% hold current. > > > > > > Remember the Xc supply ALWAYS runs full current, > > > so if your 120mA relay is OFF, something else > > > (large zener?) must be drawing the 120mA. Have a > > > serious think about this. Xc supply is best for > > > circuits that always draw the same current. > > > :o) > > > -Roman > > > > > > -- > > > http://www.piclist.com hint: PICList Posts must start with ONE topic: > > > [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads > > > > > > > > > >-- > >http://www.piclist.com hint: PICList Posts must start with ONE topic: > >[PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads > > -- > http://www.piclist.com hint: The list server can filter out subtopics > (like ads or off topics) for you. See http://www.piclist.com/#topics > > -- http://www.piclist.com hint: To leave the PICList mailto:piclist-unsubscribe-request@mitvma.mit.edu