> > The output will actually be
> >proportional to the current and its frequency
>
> Actually a current transformer (CT), if you terminate it in a low enough
> resistance will be independent of the frequency over a wide range.

All true, but I wasn't talking about a current transformer.  I specifically
mentioned measuring the open circuit voltage of the secondary.  In a current
transformer, you essentially measure the short circuit current of the
secondary.  Both will work here, but I thought the open circuit method would
present a slightly more desirable load to the circuit under test and would
have a better frequency response when used with the single pole low pass
filter.


********************************************************************
Olin Lathrop, embedded systems consultant in Littleton Massachusetts
(978) 742-9014, olin@embedinc.com, http://www.embedinc.com

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