I am using ASM in MPLAB.

Thank you Andy for your help!
Thomas

>From: "Robert E. Griffith" <bob@JUNGA.COM>
>Reply-To: pic microcontroller discussion list <PICLIST@MITVMA.MIT.EDU>
>To: PICLIST@MITVMA.MIT.EDU
>Subject: Re: [PIC]: Display Method.  Need help!
>Date: Thu, 26 Jul 2001 19:42:29 -0400
>
>What are you programming in? ASM, C? If you are using the CSS compiler, I
>just found out this trick a couple of days ago (see the "string cheese"
>thread) from (I think it was) Hans.
>
>Even though the rtl has not sprintf or itoa functions it has a printf.
>Printf can be redirected to a string or to an LCD display like this.
>
>void displayCharOn(char ch)
>{
>         // copy char to next location on display
>         // increment next display position
>}
>
>{
>...
>         printf(displayCharOnLCD, "The value is %ld", adValue32);
>}
>
>--BobG
>
>-----Original Message-----
>From: pic microcontroller discussion list [mailto:PICLIST@MITVMA.MIT.EDU]On
>Behalf Of Thomas N
>Sent: Thursday, July 26, 2001 7:28 PM
>To: PICLIST@MITVMA.MIT.EDU
>Subject: [PIC]: Display Method. Need help!
>
>I am using the PIC16F877 with an 16x2 LCD module.  I am trying to display
>the A/D results on the LCD, 4 numbers per each row.
>
>What I did is that I set aside 32 bytes of memory and each byte of memory
>represents one ASCII character on the LCD (16 bytes for Line 1 and the
>others for Line2).  Then I store the A/D results in appropriate
>"coordinate"
>in the memory.  After that, I "copy" the entire memory block (the 32 bytes
>block) to the LCD.  Whenever I want to update a certain A/D number, I go to
>its memory location and update the number, then do the "copy" to the LCD
>again.
>
>Is there a better way to do this?  There must be...
>
>Another "pain" I have to go through is to convert the A/D number to ASCII.
>Let say the A/D result is 173 decimal, I have to separate number 1, number
>7, and number 3.  Then covert them to ASCII, then store them in the memory
>block, then copy the memory block to the LCD.
>
>There must be a better way to do this too, right?
>
>Thank you in advance!
>Thomas
>
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