Mike Mansheim wrote:
>
> Hey Roman - I know this hasn't been mentioned for a while,
> but I was wondering:  how do you physically implement
> the 5% resistors?
> Thanks.


Hi Mike, the idea is to drop 5% of the mains
voltage across the series resistor and 95%
across the bulb. 8% is even better.

Assuming 120vac mains, 60w bulb, gives 0.5amp,
so you need about a 12 ohm resistor, which drops
about 6v. It will dissipate 3w, so use a 10w
resistor, which will still get hot.

You may need to fiddle with resistor values
to get a result you are happy with. :o)
-Roman

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