Regarding the wall warts, (or any power supply or transformer for
 that matter), the open circuit voltage will be significantly higher
 than the sepcified voltage because it is unloaded.  Just to refresh
 everyones memory, the voltage/current rating on a transformer or
 power supply tells you the terminal voltage at a given current draw.

 For instance, a wall wart rated at 9VDC at .75 amps lets say.  This
 means that the terminal voltage will be 9V when a current of 750 mA
 is being drawn from it.  The open circuit voltage may be 15-20 VDC
 as you are seeing here.

 Just thought I'd refresh everyones memory.  I know I sometimes
 forget basic things such as this, and often it drives me nuts
 until I remember.  Then I wonder why I didn't thinks of that
 before, or more to the point why I forgot in the first place.

                                             Regards,

                                               Jim
On Mon, 09 July 2001, Bob Barr wrote:

>
> John Waters wrote:
>
> >
> >15V at "NO" current (although marked as 9V on the wallwart).
> >
>
> That's pretty typical for the unloaded output on a 9-volt wallwart.
>
> As you increase the load, the will usually drop off fairly quickly.
>
> Don't be surprised if the output remains above 9 volts as you crank up the
> load. Many of these devices will still put out 10 or so volts even when
> pretty heavily loaded. (Of course, YMMV.)
>
> Regards, Bob
>
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jim@jpes.com

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