S Parkis wrote:
> If you divide 0x400E by 2, you get your desired 0x2007.
>
> I think we're seeing some history in the format of the .hex file.
> We're using a byte-oriented format to express 14-bit word entries,
> so the indicated addresses are essentially byte locations.  Note the
> second line, which I've broken up into pieces to make the point:
>
> :10 0010 00 8130.9900.9816.1815.8312.9817.F030.8600 D1
>
> We know this is really destined for word locations 0x008 through
> 0x00F--not 0x010 through 0x017--since it follows the code in
> the previous line directed at 0x000 through 0x007. The indicated
> length is 16 (0x10), but there are only eight words provided.
>
> Bottom line: divide the indicated address by two to derive the 14-bit
> word location to be programmed.

Now it makes sense. Thanks.

You mentioned history, does that mean there's a reason why its done this
way?

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