I was confused Mark's solution, too.  I (accidentally) sent my question
directly to David.  Here's how he explained it to me:

"TIMER0 will generate an interrupt when it overflows from FFh to 00h

have your interrupt routine count these overflows, 25 of them in his
example will get me to .250 since it's .01 per"

Makes sense to me...
W

> And how do we get this counter to equal .250 seconds?  Have it overflow 3
times
> and you only have .196608 seconds.  Loop it 4 times and you have .262144
> seconds.  You would need count about 3.8147 times.

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