Mark Peterson <PICLIST@mitvma.mit.edu> wrote:

> For lack of better teminology, what is the long hand math version of
> taking a number to a non-integer power?
>
> For example, if I have 2.72^1.23, how can I calculate the result if an
> x^y function is not available?

Mark:

If you can calculate or lookup logarithms, use:

    x ** y = antilog (log(x) * y)

For example:

    2.72 ** 1.23 = antilog (log(2.72) * 1.23)
                 = antilog (0.4345689 * 1.23)
                 = antilog (0.5345198)
                 = 3.4238896

It doesn't matter whether you use log base 2, log base 10, or log
base e.

-Andy


=== Andrew Warren --- aiw@cypress.com
=== IPD Systems Engineering, CYSD
=== Cypress Semiconductor Corporation
===
=== Opinions expressed above do not
=== necessarily represent those of
=== Cypress Semiconductor Corporation

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