Yes, I did something careless yesterday... I have an external analog source
0-4.1 V that I have to use a clip lead to connect the output of one circuit
into the PIC's A/D input.  I have a 4.096 Vref into the PIC's Vref.

However, in my haste to get a test going, I accidentally forgot to clip the
analog source into the PIC's A/D input pin, so it was just left floating.
Later, I noticed that my Vref is no longer accurate at 4.096, but instead is
around 4.80 V.

My question is: could I have partially burned out the voltage reference by
leaving that pin floating?  The code always attempts to read the pin, so
yes, the PIC was actively trying to read the input.  Not being an EE myself,
I don't really understand what happens in these circumstances, I just try
not to do things like this :)

--Andrew
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