> Just double checking this.  At 4MHz, the timer will interrupt every:
> 256((2^(prescaler+1)/(2^22)) seconds.  So with a 0 prescalar you'll be
> getting an interrupt every: 256(2/(2^22)) seconds (122us)?  This appears
to
> be the smallest obtainable period with this clock speed.  If anyone can
> confirm this, it'd be much appreciated!!

I didn't follow where you got your numbers from.  But, the fastest free
running timer 0 interrupt will be every 256 instructions, which is every
256uS with a 4MHz oscillator.


********************************************************************
Olin Lathrop, embedded systems consultant in Littleton Massachusetts
(978) 742-9014, olin@embedinc.com, http://www.embedinc.com

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