Thanks for that, I didn't think of re-arranging it that way.
Actually, I can probably make the constant 256 which
means that I could put B in the high byte and then divide
by A. The error would be acceptable for the intended usage.
So all I really need is a 16 bit / 8 bit divide routine then?
That will give me a 16 bit result for my counter won't it?

Graham wrote:
>For best resolution, you need to do a 16 bit multiply (B * 255)  and then
>divide by A.

> > > I need to implement the following equation in a 16F876.
> > > RESULT = (255 / A) * B
> > > A and B are bytes (each have possible values of 01 to FF)
> > > RESULT is a word (unsigned) for a timer routine counter.
> > > Speed is not an issue. Code space is not really either.
> > > What's the best way to do this sort of thing?
> > > Regards...

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