> Perhaps take out the 10R resistors leaving the LED open circuited, and
> see oABw happens.
>
> Alternately, recalculate the resistors and connect the LEDs to the
> supply rail before the 5V reg.

Another alternative would be to put a resistor between emitter and ground,
and lose the base resistor.  This makes the transistor function as a current
drain instead of a saturated switch.  The drawback of this is that it eats
up about 4.5V.  This is only OK if your unregulated supply is high enough to
drive the LEDs minus 4.5V.


********************************************************************
Olin Lathrop, embedded systems consultant in Littleton Massachusetts
(978) 742-9014, olin@embedinc.com, http://www.embedinc.com

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