At 11:34 PM 3/14/01 +0100, you wrote: >I have finished a IR proximity sensor with a 556 (<=> 2x555), >an IR led and an IS1U60. In order to save mA I need to reduce >the duty cycle of my 555's. > >Somebody knows how to make a 555 oscillate with a duty cycle >smaller thab 0.5 ? > >Note : duty cycle = ratio of the time duration when the ouput >pulse is high to the total period. One way is to leave 7 open, connect 2 & 6 together & to cap, as usual, and connect two resistors in series with diodes, back to back between 2&6 and 3. This works better with CMOS 555 and output lightly loaded. 6 & 2 --x----|<|----- R1 -----x--- 3 | | x----|>|------R2 -----x Ton = k * R1 Toff = k * R2 Duty cycle = Ton/(Ton+Toff) = k * (R1/(R1+R2)) So, just make R1 < R2 to get < 50% duty cycle Best regards, =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= Spehro Pefhany --"it's the network..." "The Journey is the reward" speff@interlog.com Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com Contributions invited->The AVR-gcc FAQ is at: http://www.bluecollarlinux.com =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= -- http://www.piclist.com hint: The list server can filter out subtopics (like ads or off topics) for you. See http://www.piclist.com/#topics