Thanks.  That looks more like the way I thought it should look.  I just
couldn't see it.

> -----Original Message-----
> From: Scott Dattalo [mailto:scott@DATTALO.COM]
> Sent: Monday, February 19, 2001 4:42 PM
> To: PICLIST@MITVMA.MIT.EDU
> Subject: Re: Code challenge
>
>
> On Mon, 19 Feb 2001, Don Hyde wrote:
>
> > I need to add a 24-bit signed number to a 40-bit total,
> using a 16CXXX
> > processor.
> >
> > What I've coded looks pretty messy by the time I've
> propagated the carries.
> > It seems really gross, and is slower than adding two 40-bit numbers!
> > Perhaps someone out there has thought about these and has
> it all worked out
> > already?
> >
> > The 24-bit number is in AARGB2 thru AARGB0 (MSB)
> > The total is being accumulated in Xsum3_2 thru Xsum3_oflo2 (MSB)
> >
> > ; Accumulate sum of cubes
> >
> >    movfw AARGB2
> >    addwf Xsum3_2,f
> >
> >    movfw AARGB1
> >    skpnc
> >    incfsz   AARGB1,w
> >    addwf Xsum3_1,f
> >
> >    movfw AARGB0
> >    skpnc
> >    incfsz   AARGB0,w
> >    addwf Xsum3_0,f
> >
> >    clrf  temp
>
> <snip>
>
>
>      rlf    temp,w         ;pick up the carry
>      addwf  Xsum3_oflo,f   ;and propogate to the upper 16bits
>      skpnc                 ;C will only be set if W=1
>       addwf Xsum3_oflo2,f  ;so we can add w to high 8.
>
> Scott
>
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