Actually, I think the 'pass' is a byte count grabbed from the early part of
the buffer.

When we saw the full loop there was an interesting "--pass" somewhere in it.

Bob Ammerman
RAm Systems
(contract development of high performance, high function, low-level
software)

----- Original Message -----
From: rostaman <rostaman@ONEBOX.COM>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Friday, January 26, 2001 11:13 AM
Subject: Re: [OT]: quick question on C


> Oluseyi:
>
> From the variable name, "rx_str", it appears that
> the for loop is traversing an array of characters,
> where the "ptr1<size" part is keeping it within the
> bounds, and the "pass" part is checking for a NULL
> character, or the end of the string.  So, the
> "pass" by itself is the same as "if (pass != NULL),
> continue", which will break out if a NULL terminator
> is seen before the end of the array is reached.
>
> Have fun!
> Ross
>
>
>
>
>
> ----         Oluseyi Odeinde <seyi@OCEAN.CF.AC.UK> wrote:
> > i apologise if this post appears more than once - just realised that the
> > 1st time i sent it, my [OT] channel was turned off!
> >
> > hello everyone,
> >
> > i came across the following 'for' statement in a code:
> >
> > for (pass=rx_str[ptr1+1]; ptr1<size && pass; ptr1++) {
> >
> > i'm curious about about the 'ptr1<size && pass' of the statement as i
> > have never come across a for loop layed out in this way.
> > 1. is this valid?
> > 2. if so, is it the same as saying 'ptr1<size && ptr1<pass' ?
> >
> > TIA
> > Seyi
> >
> > --
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> >
> >
>
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