All,

  Or just add NOP's to fine adjust the routine.

                              Regards,

                                Jim



On Thu, 04 January 2001, Drew Vassallo wrote:

>
> This should get you 0.985 seconds, which seems ok, unless you need better
> precision:
>
> ;; Uses 2 registers as counters plus W
> Delay_1sec
>         movlw   0x03        ; 3 * .328secs = .985 seconds
>         movwf   Counter2
>         clrf    Delay_Count ; 256 loops @ 256*5us each ~= .328secs
>         clrw
> Delay_L
>         addlw   0x01
>         btfsc   STATUS, Z   ; check for overflow past 0
>         decfsz  Delay_Count
>         goto    Delay_L
>         decfsz  Counter2
>         goto    Delay_L
>         return
>
> If you need better precision, you can preload Delay_Count with a lower value
> to make it overflow faster for the first loop, then increase Counter2 from
> 0x03 to 0x04 to get that extra 15ms you need to bring it to 1.000 seconds.
> I'll let you do the math.
>
> --Andrew
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jim@jpes.com

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