> That would apply to a spot wouldn't it ? If there's a line then the power
> will be spread out. Assuming 100% lens efficiency, a 5mm round spot
> has thinned out (at 10m, 120 degrees arc) to a 200,000mm x 5mm
> spot or 1/40,000th

Oooops. 20,000 x 5 = 1/4000 = 0.25uW per 5x5mm with 1mW source

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