> i.e How can i calculate the nop delay if working with a 4MHz crystal.
> I've seen many examples that calculate this delay in various ways but the
> result is not the same.

It takes 4 clock cycles to execute each simple instruction like a NOP.  With
a 4MHz clock you can run instructions at a 1MHz rate, which means the delay
for an individual NOP is 1uS.


*****************************************************************
Olin Lathrop, embedded systems consultant in Devens Massachusetts
(978) 772-3129, olin@cognivis.com, http://www.cognivis.com

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