OK, I got some food  in my stomach so I can think a little
more clearly now.

You'll only need 4 pins to give you 12 LED's with this
method. You can light any LED at any time OR if you
need all on, you'll need to multiplex them.

The pins that are not actively driving the LED in question
(only two pins are active at any one time) need to be set
to tri-state (inputs).

Let me try and draw a picture:

First,    each LED is back to back with the other, such as:

->|-     and
-|<-   meaning each anode is hooked to the cathode of the other
in each two LED group. I will represent this as a -**- in my drawing,
where each "**" represents two LED's back to back.

O is a PIC PIN

So here we go:


|------------**------------|
|                          |
|        |-------**--------|
|        |                 |
|-------**--------|        |
|        |        |        |
|---**---|---**---|---**---|
|        |        |        |
O        O        O        O

12 Leds from 4 pins.

I left out the currently limiting resistors, but you'll
need to add them directly at the PIC pins... don't
forget the current will be going through two resistors,
so make sure each is half of the final value.


Jeff