Hi David, One way to perform a "reality check" on situations like this is to think about what the device "sees". In order for a device to "see" 5 volts on one of its pins, the 5 volts must be referenced with respect to one of its other pins. In the case you gave, the 5 volts was with respect to GND,but none of the transistor's pins were grounded. Therefore, as far as the device was concerned, there its gate-source voltage was not 5V but -2V,definately not what would turn it on. As others suggested, tieing the source to ground made the 5V GND-referenced input actually look like 5V to the FET,too. Sean At 08:27 PM 12/8/99 -0500, you wrote: >I am working on a project that uses a PIC to operate 3 logic level HEXFET's >(IRLIZ44N & IRLD014) that is driving me crazy. I was under the impression >that logic level HEXFET's would (when +5V is applied to the gate) would open >up an pass whatever voltage was on the drain to the source (within the >limits of the device). Ain't happening. All I get is 6 - 7 v through the >device, with 24vdc on the drain. And yes, I do have the gate, drain, source >pins correctly identified. I have tried high side, low side and would try >third side if I knew how. > >Basic circuit is > +24vdc > | > Drain > +5V------Gate > Source > | > 24 vdc relay coil > | > GND > >To date I have not even put the PIC in the circuit, but rather just fed 5v >from the power supply. >Any ideas or help would be greatly appreciated - I am beginning to doubt my >manhood! >Thanks >David > | | Sean Breheny | Amateur Radio Callsign: KA3YXM | Electrical Engineering Student \--------------=---------------- Save lives, please look at http://www.all.org Personal page: http://www.people.cornell.edu/pages/shb7 mailto:shb7@cornell.edu ICQ #: 3329174