instead of driving the anode of the LED turn it around so you drive the
cathode with the other end to 5v.
the PIC can sink more than it can source.

        cya,    Andrew...

> -----Original Message-----
> From: Graham North [SMTP:graham.north@LANDINST.COM]
> Sent: Wednesday, 8 December 1999 21:24
> To:   PICLIST@MITVMA.MIT.EDU
> Subject:      509 flasher
> Importance:   High
> Sensitivity:  Confidential
>
> I have tried this program and it will not work!  (shown below)
>
> Pins 6 and 7 are doing something, but they only switch between 0 and
> around
> 1.7 volts!
>
> It is wired up like this:
>
> Pin 1 +5V
> Pin 2 NC
> Pin 3 NC
> Pin 4 NC
> Pin 5 NC
> Pin 6 ---------/\/\/\/\/\---------|>|---------Gnd
>                         330 ohm
>
> Pin 7 as pin 5
> Pin 8 Gnd
>
> Have you any ideas?
>
> Graham
>
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