You could use a union as follows:

union intchar
{
        struct{
                unsigned char lo;
                unsigned char hi;
                }byte;
        unsigned int total;
}

union intchar timer1;
union intchar myvar;

timer1.lo = TIMER1L;
timer.hi = TIMER1H;
myvar.lo = CCPR1L;
myvar.hi = CCPR1H;

myvar.total += timer1.total;
CCPR1L = myvar.lo
CCPR1H = myvar.hi

Probably not very efficient though...

Regards

Mike Rigby-Jones

-----Original Message-----
From:   Roberto Fonseca Iannini [SMTP:roberto1@LINKEXPRESS.COM.BR]
Sent:   Tuesday, November 09, 1999 2:44 PM
To:     PICLIST@MITVMA.MIT.EDU
Subject:        8 + 8bits variable

What's the c syntax to perform an 16-bit sum like:
CCPR1 = CCPR1 + TIMER1;
Note that TIMER1 wasn't defined by the 1687x.inc. Instead it was made as
TIMER1H and TIME1L (each one 8 bits type). The same is true to CCPR1.
Summarizing: How can I define or use  a new 16 bit variable called
TIMER1 that is formed by TIMERH and TIMERL (MSB and LSB)?
(this code is for 16F877)
See you guys,

Beto.