Your syntax is correct.

To make TIMER1 you could use:
unsigned long (uns16, etc) TIMER1;
TIMER1 = TIME1L + TIME1H * 256;

Regards,

Brusque

----- Original Message -----
From: Roberto Fonseca Iannini <roberto1@LINKEXPRESS.COM.BR>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Tuesday, November 09, 1999 12:44 PM
Subject: 8 + 8bits variable


> What's the c syntax to perform an 16-bit sum like:
> CCPR1 = CCPR1 + TIMER1;
> Note that TIMER1 wasn't defined by the 1687x.inc. Instead it was made as
> TIMER1H and TIME1L (each one 8 bits type). The same is true to CCPR1.
> Summarizing: How can I define or use  a new 16 bit variable called
> TIMER1 that is formed by TIMERH and TIMERL (MSB and LSB)?
> (this code is for 16F877)
> See you guys,
>
> Beto.
>