A note about polarity and phone connections: The two wires of an analog telephone connection are called Tip and Ring. Tip is normally at ground potential. Ring is normally at minus 48 volts with res pect to ground, not + 48 volts as the diagram shows. Negative battery supplies (with respect to ground) have always been used with phone systems, so that leak age currents to ground caused by moisture do not electroplate away the copper in the wires. Some modems, e.g. certain US Robotics models, do not work correctly if the polarity is reversed (they will not detect ring), but most modern modems use diode bridges so that polarity doesn't matter. The 2KOhm resistor shown s hould work fine, but it only provides about 1/2 the normal current that each mod em normally expects to see-- (each phone wants to 'see' about 20 ma) -- this sho uld work fine, tho 1K to 1.5K would be more accurate. Wagner's ring circuit is very clever, do you see that when the relay contact swi tches, the phone 'sees' a change of 96 volts. But be sure you get the capacitor the right way, or you will have quite an explosion, and with tantalum caps, you will have flames. The transformers shown are 'inside' the modem -- but the vast majority of modem circuits do not pass the loop current thru the transformer, because the transfor mer core size required to avoid saturation means you need a bigger more expensiv e transformer. They couple to the transformer thru a cap, and send the loop cur rent thru a resistor or resistive bridge. Wagner, you have a great way with ASCII-based circuit diagrams! Regards, Ron Fial -------------------------------------------------------------- >>Wagner Lipnharski wrote >If you want to simulate the phone line voltages and currents: > > + 48Vdc > | > R 2 kOhms > Current R >Modem #1 <--- | ---> Modem #2 > | >---. .----RRR------o------RRR----. .--- > 3|( 150 Ohms 150 Ohms 3|( > 3|( 3|( > 3|( Phone Line 3|( >---' '-------------o--------------' '--- > 600 Ohms | 600 Ohms > Ground >