I am attempting to use this delay code from:
http://www.dontronics.com/rtc.html#pic2

>From what I can work out the equation gives the number of instructions
which are executed. I am using a PIC16F84 (10Mhz) and want to know who to
convert instructions to time. I have gone through th F84 data sheet and it
doesn't specificly say how many clock cycles are used per instruction. It
says 'cycles' but this is 1 or 2 and 0.1uS sounds a bit small.

Thanks for your help in advance.

Wesley

The routine is below, it may have been mucked up by the mail program
(wrapping). The link above will take you to the original version.

delay           movlw   0x001           ;standard delay routine. increase
w value
                movwf   count1          ; for increased delay
                movlw   0x001           ;can set up any delay by calling
delay1 (NB!)
                movwf   count2          ; with pre-set values in count1,
2, 3
                movlw   0x020           ;ex Myke Predko, piclist 4 Jan97
                movwf   count3          ;delay, (no of instructions)=
delay1          decfsz  count3,same     ;2 + 5*(count3-1) +
                goto    $-1             ;2 + (5*255 +2+5) * (count2-1) +
                decfsz  count2,same     ;2 + (5*255*256 +2 + 5*255 +2+5)
*(count1-1)
                goto    $-3             ;  =
                decfsz  count1,same
;5(count3-1)+1282(count2-1)+327684(count1-1)+6           &nbp;
                goto    $-5             ;        return                  ;