On Thu, 17 Jun 1999, Clyde Smith-Stubbs wrote:
>(byte2 &= ~BITMASK2), (byte1 & BITMASK1) && (byte2 |= BITMASK2);

That is food for thought. Let me see if I get this.

(byte2 &= ~BITMASK2), (byte1 & BITMASK1) && (byte2 |= BITMASK2);
                                |         |         |
Ok I can see this works,        |         |         |
since this part gets evaluated -+         |         |
and if it's false then                    |         |
because of the logical AND ---------------+         |
then the last part is not evaluated ----------------+
and the assignment does not take place.

But it is a little too scary for me to actually use. I'll stick to:

(byte2 &= ~BITMASK2), (byte1 & BITMASK1) ? (byte2 |= BITMASK2) : 0;

Thanks for the good examples, it's opened my eyes up a lot to the
intricacies involved when combining logic and math in one statement.

Best regards,
Bob