Find out for yourself... solve the equation I gave you and replace GND
with +5.


> At 01:55 03/19/99 -0500, Vincent Deno wrote:
> >> several months ago I asked a question about bipolar A/D inputs....say,
> >> -5v to +5v.  Someone suggested something using just a couple of
> >> resistors to use as a voltage divider.  Could anyone say that again?
> >> All of my messages were deleted....
> >
> >What they were probably referring to was:
> >        Vin ----+
> >                <
> >                < R1
> >                <
> >                |
> >                +--- Vout
> >                |
> >                <
> >                < R2
> >                <
> >                |
> >                GND (=0V)
> >
> >(Finally) => Vout=(Vin*R2)/(R1+R2)
>
> the problem with this is that a negative input results in a negative output. i
n
> the case of -5..5V => 0..5V, it is better to reference the divider to the 5V,
> like this:
>
>                 +--- +5V
>                 <
>                 < R1
>                 <
>                 |
>                 +--- Vout
>                 |
>                 <
>                 < R2
>                 <
>                 |
>         Vin -----
>
> Now the output is (if you make R1=R2) 0..5V
>
> ge
>

--------------
Vincent Deno
Design Engineer
Theta Digital Corp.
www.thetadigital.com
denovj@email.uc.edu
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