Sean Breheny wrote:
> Thanks,but the main thing that I don't understand is why this might result
> in MOSFETs being damaged,as in the post which I replied to.
The MOSFET will be damaged because it will remain ON always.
Example, if PORTA:0 drives a FET and PORTA:1 is an input, if your code
has:

        movlw   1
        movwf   PORTA           ;turn on FET
        .
        .
        .
        bcf     PORTA,0         ;turn it OFF again for after some time
        nop                     ;this can help if w/ a series resistor
        btfss   PORTA,1         ;test input !!!READ-MODIFY-WRITE
         goto   do_something
        goto    do other

At this point, the pin will remain HIGH because of the btfss reading the
pin again while the gate is still charged.

> I ESPECIALLY don't understand why the positioning of the resistor along the
> line between the gate and the PIC would matter when it came to protecting
> the FET.
I don't understand this also.  Maybe the inductance of the wire will
cancel the capacitive effect??!!

regards,
Reggie

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