I tried your routine ,using MPSIM and I found out that the number
instruction pass from the begining to the end of routine 536609
instructions.
if you use 4Mhz crystal then the T crystal = 0.25 usec .T instruction = 1
usec.It means your routine isn't for delaying 1 sec because 536609 X 1 u sec
=
536609 u sec .You have to trim counter content to get 1 sec delay.
Correct me if I am wrong.

Hanafi T

>Here is the code for a 3byte counter wich results in a delay of 1 second.
>This code is written for a 4MHz crystal

>DELAY
>    MOVLW      005H
>    MOVWF      COUNTER               ;MSB VAN DE DRIE BYTE TELLER
>    MOVLW      016H
> DELAY0
>    MOVWF     COUNTER1
>    CLRF          COUNTER2              ;LSB VAN DE DRIE BYTE TELLER
> DELAY1
>    DECFSZ     COUNTER2,F          ;DEZE INSTRUCTIE DUURT 1uS !
>    GOTO          DELAY1                    ;DEZE INSTRUCTIE DUURT 2uS !
>    DECFSZ     COUNTER1,F
>    GOTO          DELAY1
>    DECFSZ     COUNTER,F
>    GOTO          DELAY1
>    RETURN
>Glenn
>