I believe that 0h is the first line and 40h is the second line,
although I can see where using 80h for the first line and
C0h for the second line would do the same as it appears
as bit 7 is getting lost in the bit bucket.

-Ralph
rlandry@haywood.main.nc.us
"If they call it Tourist Season why can't we shoot 'em?"
ICQ# 19545315
-----Original Message-----
From: Todd Peterson <toddp@ELABINC.COM>
To: PICLIST@MITVMA.MIT.EDU <PICLIST@MITVMA.MIT.EDU>
Date: Thursday, October 08, 1998 5:11 PM
Subject: Re: LCD Problem II


>At 07:30 PM 10/8/98 -0400, you wrote:
>
>>I can write to the first line of the LCD fine, but I can't find any way
>>that lets me write to the second. If I try just sending more than 16
chars,
>>the ones that come after 16 don't get printed. If I try to set the address
>>register, the same thing happens. Apparently, I can't find the right
>>address for the second line. Some body had suggested that the address for
>>the first line was 0x80 and 0xC0 for the second. Well 0x80 works for the
>>first line, but when I write to 0xC0, I get no output. I also tried 0xA0
>>and 0x90, and neither worked.
>
>Sean,
>
>If it's a 16x1, $80 is the first 8, and $C0 starts the second 8.
>
>Are you certain you are senidn ghte $C0 properly, as an instruction and not
>as data?
>
>
>
> Todd Peterson
> E-Lab Digital Engineering, Inc.
> (816) 257-9954
> Embedded Control & Integrated Circuit Solutions...
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>
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