>> This also as the effect of minimizing the effect of the pickup
>> inductance since it's working into a short. It ruins the Q, making
>> the transducer much more wideband, and removes almost all
>> of the self-resonance problems.
>>
>I think that this is the REAL reason why the current to voltage converter
>works best, because the loop sees a short. The easiest law to apply to
>this case will be Lenz's, implying that the loop is inherently a current
>producer, however, I think that if you measured the total resistance of
>the circuit and multiplied by the current, the voltage you would see
>would be that given by Faraday's law.


I agree with what you said, but IMHO, the basic phenomena is that
charged particles traversing a magnetic field are deflected. You can't
define a voltage until there is a resistance.  That's where Faraday
and Lenz take opposite paths (or join, depending on your point of
view :)

The real coil will have some R, and so will retain some L, and will
still have a self resonant point, but the effect of this on the circuit's
performance in the real world will be very small.

I came into this from the opposite direction as well, having tons
of experience with magnetic read heads and credit cards, and
amplifying the head as a voltage. It's really rather miserable.
Once I figured out this approach, things got a WHOLE lot simpler.
We no longer need sheilded cables either!

>I know that what I am saying is REALLY splitting hairs, but I just want
>to see how well what I have learned applies to real life situations :)


Good deal!  Rabbit blood everywhere :)
The fun part is when the real circuit departs from the theoretical in ways
that are difficult to measure!