Thanks for the help!!  It was much needed and appreciated!
-----Original Message-----
From: Mike Keitz <mkeitz@juno.com>
To: PICLIST@MITVMA.MIT.EDU <PICLIST@MITVMA.MIT.EDU>
Date: Sunday, May 03, 1998 7:35 PM
Subject: Re: [OT] windows terminal- output?


>On Sun, 3 May 1998 17:46:45 -0400 Bill Kennedy <hue@FRONTIERNET.NET>
>writes:
>>Piclist,
>>    Anyone know what windows 3.1 terminal program actually sends out
>>the
>>serial port?
>
>Unless it is very strangely configured, it sends ASCII characters.  The
>ASCII code for '0' is 0x30 and the ASCII code for '9' is 0x39.
>
>I am trying to send data characters 0-9, but don't quite
>>recognize what I see on the scope.  I've set up communications setting
>>to
>>7-n-1.
>
>On a RS-232 line, zero bits are + voltage (typically 5 to 12V) and one
>bits are -voltage (typically -5 to -12V).  Each bit stays at the
>designated voltage for the duration of 1/baud rate, then the next bit is
>sent immediately.  When no data is being sent, the line idles at -
>voltage.  Before each character of data is sent, a 'start bit' of one bit
>duration of + voltage is sent.  The data comes out LSB first.  After the
>last bit, the line stays at - voltage for at least one bit time (the
>'stop bit').
>
>So if you type '1', which is ASCII 0x31 or 0110001 binary, the RS-232
>signal would be:
>+-+++--+-
>S1000110K
>time -->
>which would look like -_---__-_ on an oscilloscope (with no gaps).  Set
>the scope to trigger on a rising edge and it should catch the start of
>the start bit.
>
>S = start bit, K = stop bit.  After the sequence, the line may stay at -
>voltage if there is nothing more to send, or a new start bit and
>character may immediately follow.
>
>
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