> My dividend is smaller than the divisor (always).
> Both are positive numbers. The dividend is in the range 0-128 and the
> divisor is in the range 0-256. The only way I know of is to implement it
> as a 16-bit by 8-bit divide. But that takes 192 instructions which is a
> lot for my application.
>
> Does anyone have any better idea how to do it?

That's a little tricky. The idea is based on a mathematical property of
the division. It is REAL FAST and VERY SHORT.

;
;  8bit / 8bit divide routine.
;
;  Enter the routine with dividend in 'dividend' and
;  divisor in 'divisor'.
;
;  Return truncated result of dividend/divisor in W.
;  NOTE: dividend MUST BE SMALLER than divisor.
;
div8x8  retlw   0

(Sorry but I couldn't resist :-))))

   Marco