At 06:47 PM 3/10/98 -0500, Sean Breheny wrote:
>         Secondly, lets suppose that there was enough wire in the cable to
create
>a significant capacitance. The effective circuit would look like a
>capacitor with a resistance in parallel (we can ignore the inductance, it
>certainly won't make much difference beyond seconds of time). The value of
>the effective parallel resistance can be approximated by the resistance of
>the cable.

Sorry, Sean.  The resistance in parallel would be the resistance of the
insulator between the two conductors, not the resistance of the wire,
itself.  This is typically *very* high.  To make calculation easier, it is
typically specified as a certain conductance per unit length (conductance
is just the reciprocal of resistance).

 - Rick "micro-mhos per meter" Dickinson
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