At 09:50 PM 2/26/98 GMT, Martin R. Green wrote:
>Great, but I think the question really referred to the bit about "just
>do the inverse".  This doesn't make sense to me.  The original
>multiplication is the easy part.

Regarding confusion over the original suggestion:

>>Simple.  To multiply by 3, double and add to original.  To divide by 3,
>>just do the inverse!

So let's see... double and add to multiply by three, so the inverse is just
subtract and divide by two....

Okay.... let's do six.  6-2=4, 4/2 = 2.  Wow, it works!

Now, to divide n by three, I just need to figure out a quick way to
calculate the number to subtract from n, which is n/3.....

 - Rick "Math is hard" Dickinson

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