From this explanation it seems like the circuit should work with a higher voltage LED. Has anyone tried to power a blue LED from a single cell? snip%<----------------------------------------------------- >>> On 2/2/98 Pasi T Mustalahti wrote: >>> >>> -------8<-------- >>> > >>> > ------------------------------------- +U (0.6..1.55 V) >>> > | | >>> > R20K || < >>> > | || < >>> > ----------------> || < >>> > | > || < >>> > = 10nF | /------>|--| >>> > | ----| BC337 | >>> > | \ | >>> > | | | >>> > -------------------------------------- >>> > > snip %< ---------------------------------------------------- >The circuit is best described as a self-oscillating flyback converter. >Each time the transistor turns on, it charges the transformer with >current until it saturates. When it saturates, the voltage induced in >the base winding decreases, causing the transistor to turn off. The >energy stored in the transformer is then dumped to the load (LED in this >case). > >For a given frequency of operation and transformer core, the circuit will >deliver approximately constant *power* to the load, regardless of the >load voltage. The power is distributed in pulses having the energy that >the transformer core can hold before it saturates. Since it always >charges until it saturates, the output power doesn't depend on the input >voltage, if (and this is a big "if"), the frequency doesn't vary. > >If the DC supplied to the transistor base circuit is adequate, the >circuit will oscillate continuously at the highes practical frequency >(depends on the input voltage and the inductance of the winding). More >likely, Pasi's circuit is running in "relaxation mode". The base current >required by each cycle discharges the capacitor somewhat, to less than >Vbe so the transistor doesn't turn on right away after the transformer >voltage reaches zero (all energy having been delivered to the LED). >There is a delay during which the resistor has to charge up the capacitor >to start the transistor conducting again. So the frequency probably >decreases significantly with input voltage as the current available thru >the resistor decreases. Varying the resistor should vary the frequency, >and thus the brightness of the LED. A diode in parallel with the >transistor base (to keep it from going too far negative) would supply >current to the capacitor while the transistor is off, and probably get >the circuit to oscillate continuously rather than in relaxation mode. >However, the resulting output power would likely be too high, and >difficult to control. > >However, the experiment shows that it had satisfactory performance over >the life of the battery. The self-regulating properties of the circuit >are apparently working well enough. > snip%<---------------------------------------------------------------- ------------------------------------------------------ Wireless Link Corp. wllink.com web site bryan@wllink.com email (408)739-5465 x103 ph (408)739-5483 fax