Harold Doesn't answer all your questions, but International Rectifier App note AN-983 gives a good explanation of how an IGBT works (www.irf.com/search/). Ron ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Ron Kreymborg Computer Systems Manager Monash University CRC for Southern Hemisphere Meteorology Wellington Road Clayton, VIC 3168 Phone : 061-3-9905-9671 Australia Fax : 061-3-9905-9689 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ On Tue, 11 Nov 1997, Harold Hallikainen wrote: > I've been looking for a way to get around the saturation voltage > of triacs and have considered FETs and IGBTs for AC switching. It SEEMS > to me that the saturation voltage on an IGBT is going to be higher than > that of a FET. I view an IGBT as a sort of darlington with an FET as the > first transistor. Is this correct? If so, the input FET can go to a > source-drain short and we still need 700 mV or so on the collector to > turn on the base. Seems that directly driving the gate of a FET would > give us lower voltage drop (just due to Rds on). > In AC applications, I've thought of putting two FETs in series > and using the intrinisic diodes to steer the current into the appropriate > FET. Again, we'll lose about 700 mV across the diode of the FET that is > being bypassed. It seems that the voltage drop will be approaching that > of a triac, and we have increased circuit conplexity to boot! > > Harold >