Hi,

> >I'm currently working with a 2x16 display and I have opted to not read
> >the display and simply wait the maximum time (The application is not
> >time critical, so I save one IO). But just to check: You should not read
> >the busy flag between the two 4 bit operations, it is only valid after
> >the whole operation is completed.
>
>
> Surely you *have* to read the busy flag between the two 4-bit reads?
> 'Busy' is bit7 which appears after the first read. After the second,
> you're looking at bits 0-3.
>
> It works OK for me like this, anyway.
>
I think you misunderstood me.  I meant that, when you write something to
the LCD, you can first check the busy flag (which requires 2 reads),
then write both nibbles to the LCD.  Don't try to check the busy flag
between the writing of the two nibbles.

Niki