I guess that is true.  I don't know what the PC in a PIC does when it
executes an instruction.  Although in a lot of MCU's and MPU's the PC is
incremented immediately after an instruction is loaded, and before it is
executed, maybe the PC is not incremented in a PIC until just before the
next instruction is loaded.

In any case, I know that in PIC assembler, $ means the _current_ line.


CIAO - Martin R. Green
elimar@bigfoot.com

----------
From:   Jim Main[SMTP:jim@EWCOMM.DEMON.CO.UK]
Sent:   Wednesday, September 10, 1997 2:44 PM
To:     PICLIST@mitvma.mit.edu
Subject:        Re: "$" (was: "Re: PIC assembly style guide")

In article <01BCBDF1.BDF131C0@ifs-greenm.sybase.com>, "Martin R. Green"
<elimar@BIGFOOT.COM> writes
>Because:
>
>   goto $       ; this is a continuous loop, hence
>   goto $-1    ; jumps to btfss   port,anotherbit
>   goto $-2    ; jumps to goto    action
>   goto $-3    ; jumps to btfsc   port,bit
>
>So there!   ;-)

>>> >        btfsc   port,bit
>>> >        goto    action
>>> >        btfss   port,anotherbit
>>> >        goto    $-3
>>>
>>> shouldn't that read $-4 if you want it to jump to btfsc port,bit ?
>>
>>    No.
>>

so in other words, the $ symbol really means 'the current line' not the
program counter ('cause the program counter is pointing to the next
instruction)

Jim
--
Jim Main