Your routine should work as it is. It will set Byte1 to all 0's and Byte2
will be equal to whatever was in Byte1 when you started...There is probably
a better way of doing this copy, but I am sure you have your reasons.
Unless you really want to do a rotate you could use:

        movf    Byte1, w
        movwf   Byte2
        clrf    Byte1

Kieran.

P.S. Sorry for including all the original mesage, but I suspect that if I
edit even a small part of it, my MSMail will scramble the entire message.

----------
From:   Clewer,Brian[SMTP:brian.clewer@TELEMATICS.COM]
Sent:   10 July 1997 18:36
To:     PICLIST@MITVMA.MIT.EDU
Subject:        Re: rotate

>I am trying to rotate one byte into another, can somebody tell me if
>the following is right?
>
>
>       movlw 0x08
>        movwf count
>loop    bcf   status, carry
>        rrf   Byte1,1
>        rrf   Byte2,1
>        decfsz count
>        goto loop
>
>Thanks,
>
>David


David, as the whole principle of this works on the carry in the status
register,  I think you need a  ' BCF    STATUS,C '   after the ' RRF
   Byte2,1' instruction to clear the carry.  It should work then (not
tested).

Brian.