>        If you look closely, you'll see that it appears in bit
>        positions 22 through 29... It seems that your "a >> 16"
>        expression was actually working like "a >> 22", right?
>
>    At this point, the answer should be dawning, but just in case it
>    isn't...
>
>        Decimal 22 = Hexadecimal 16.
>
>        Oops.

oops, oops yep I did think it is something simple, I usually always
declare radix dec but hence I wrote a simple 5 lines test program I forgot,

so let it be a reminder to cross check everuthing inclunding correct
radix, if thing dont look they way they should

oh, shame shame on me :)

antti

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