NEIL GANDLER wrote: > I have a need for an 8 bit divide routine. I need to divide two 8 > bit values, where my only concern is in the quotient, not necessary > the remainder. Perhaps somewhat has something similar to what I > need. Neil: See the answer to Question #64, in the PIC section of the "Answers" area on my company's web page. For help with your high-noise automotive environment, you may also want to look at the answer to Question #4, in the Miscellaneous section. -Andy Andrew Warren - fastfwd@ix.netcom.com Fast Forward Engineering, Vista, California http://www.geocities.com/SiliconValley/2499